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NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice

Consider the following diagram in which an inextensible string connects two blocks passing via ring. The first block moves with a velocity of 2 m s - 1 and the second one moves with a velocity of v m s - 1 . If the ring slides on horizontal rod then the value of v is (in m s - 1 )

Options

  1. A3 2 + 1
  2. B3 2 + 1
  3. C2 3 + 1
  4. D2 3 + 1

Correct answer

B. 3 2 + 1

Step-by-step solution

The length of the string will remain constant. Hence, 2   cos 30 ° - 1 cos 30 ° = v cos 45 ° - 1 cos 45 ° ∴     v - 1 2 = 3 2 ∴     v = 1 + 3 2

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