NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
In the following arrangement, the system is initially held at rest by an external agent. At t = 0 , the 5   kg block is released. If the acceleration of block C is x 10   m s - 2 , then find the value of x . Assume that the pulleys and strings are massless and smooth. [ g = 9.8   m s - 2 ]
Correct answer
7
Step-by-step solution
Block B will not move 5 g - T = 5 a ...(i) 2 T - 8 g = 8 a 2 ...(ii) 2 g = 14 a a = g 7 ∴ a 2 = g 14 = 9.8 14 = 7 10 m s - 2 = 0.7 ∴ x = 7