NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
When forces F 1 , F 2 , F 3 are acting on a particle of mass m such that F 2 and F 3 are mutually perpendicular then the particle remains stationary. If the force F 1 is now removed then the acceleration of the particle is
Options
- AF 1 m
- BF 2 F 3 m F 1
- CF 2 - F 3 m
- DF 2 m
Correct answer
A. F 1 m
Step-by-step solution
According to equilibrium total force acting on a particle remains zero F 1 → + F 2 → + F 3 → = 0 F 2 → + F 3 → = - F 1 → ∴ a = F 1 m