NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
There is a trolley in which there is a fixed inclined surface on which a smooth block of mass 5 kg is placed. Two horizontal forces of magnitude F 1 and F 2 are applied on the trolley as shown to keep the trolley at rest. The value of F 1 - F 2 is : (Assume there is no friction between the trolley and horizontal ground and g = 10 m s - 2 )
Options
- A0   N
- B24   N
- C- 24 N
- D- 30   N
Correct answer
C. - 24 N
Step-by-step solution
There is a trolley for which F 1 + N sin 37 ° = F 2 F 1 - F 2 = - N sin 37 ° . . . (1) N = m g cos 37 ° . . . (2) F 1 - F 2 = - m g cos 37 ° sin 37 ° = - 5 × 10 × 4 5 × 3 5 = - 24 N