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NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice

All surfaces shown in the figure are smooth. The system is released with the spring unstretched. In equilibrium, compression in the spring will be -

Options

  1. Am g 2 k
  2. B2 m g k
  3. CM + m g 2 k
  4. Dm g k

Correct answer

D. m g k

Step-by-step solution

Let N be the normal reaction between m and M , Equilibrium of M N sin ⁡ 45 ∘ = k x ... (i) Equilibrium of m in vertical direction gives N cos ⁡ 45 ∘ = m g ... (ii) From Eqs. (i) and (ii), we get x = m g k

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