NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
The kinetic energy K of a particle moving along a circle of radius R depends upon the distance s , as K = a s 2 . The force acting on the particle is-
Options
- A2 a s 2 R
- B2 a s 1 + s 2 R 2 1 2
- C2 a s
- D2 a
Correct answer
B. 2 a s 1 + s 2 R 2 1 2
Step-by-step solution
K = a s 2 ⇒ v = 2 a m s ⇒ d v d t = 2 a m d s d t = 2 a m s The net force on the particle is F = m v 2 R 2 + m d v d t 2 = 2 a s 2 R 2 + ( 2 a s ) 2 = 2 a s 1 + s 2 R 2 1 / 2