A ring of mass 5 kg sliding on a frictionless vertical rod connected by a block B of mass 10 kg by the help of a massless string. Then at equilibrium, the value of θ (in degree) is

Step-by-step solution

For ring, From force diagram of ring, T cos ⁡ θ = m 1 g ......(i) For block B. m g = T ........ (ii) T cos ⁡ θ = m 1 g m g cos ⁡ θ = m 1 g ∴ cos ⁡ θ = m 1 m = 5 10 = 1 2 ⇒ θ = 60 o