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NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice

Two blocks of masses m 1 and m 2 being connected with a light spring of stiffness k are driven with forces F 1 and F 2 on a smooth horizontal plane. If the blocks move with the same acceleration a 0 , the value of a 0 is:

Options

  1. AF 1 - F 2 m 1 + m 2
  2. BF 1 m 2 - m 1 F 2 m 1 + m 2 2
  3. C1 2 F 1 m 1 + F 2 m 2
  4. Ddecided by the stiffness of the spring

Correct answer

A. F 1 - F 2 m 1 + m 2

Step-by-step solution

Both the blocks can be chosen as a system, thus, a 0 = F 1 - F 2 m 1 + m 2

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