NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
A body of weight 64 N is pushed with just enough force to start it moving across a horizontal floor and the same force continues to act afterwards. If the coefficients of static and dynamic friction are 0 . 6 and 0 . 4 respectively, the acceleration of the body will be (Acceleration due to gravity = g = 10 m s - 2 )
Correct answer
2
Step-by-step solution
Weight of the body =   64   N   so the mass of the body m = 6.4   kg , μ k = 0.4 Net acceleration = Applied force -Kinetic friction Mass of the body = μ s m g − μ k m g m = ( μ s − μ k ) g = ( 0.6 − 0.4 ) g = 0.2 g = 2   m   s - 2