NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
A 2000 k g rocket in free space expels 0.5 k g of gas per second at exhaust velocity 400 m s - 1 for 5 s . The increase in the speed of the rocket in this time is
Options
- A2000 m s - 1
- B200 m s - 1
- C0.5 m s - 1
- Dzero
Correct answer
C. 0.5 m s - 1
Step-by-step solution
d m d t × u = M d v d t 0.5   ×   400 = 2000   × ∆ v 5 ⇒ ∆ v = 0.5   m  s - 1