NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
Water from a hosepipe of radius 5 cm strikes a wall at a speed of 5 m s - 1 normally and stops. The force exerted on the wall in newton is
Options
- A13.5 π
- B6.25 π
- C62.5 π
- D27 π
Correct answer
C. 62.5 π
Step-by-step solution
Given, Radius of hose pipe r = 5  cm = 5 × 10 - 2  m Speed of water v = 5  m  s - 1 We know that, F = A v 2 ρ F = π r 2 v 2 ρ F = π 5 × 10 - 2 2 5 2 × 1000 F = 62.5 π N