An aeroplane is flying at a velocity of 900 k m h - 1 loops a vertical circular loop. If the maximum force pressing the pilot against the seat is five times his weight, what would be the diameter (in m ) of the loop? [ g = 10 m s - 2 ]

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Correct answer: 3125

v = 900 km h - 1 = 900 × 5 18 = 250 m s - 1 the maximum force is at the bottom of the vertical circle F max = m v 2 r + m g = 5 m g v 2 = 4 gr r = v 2 4 g = 250 2 4 10 = 1562.5 m d = 2 r = 3125 m

An aeroplane is flying at a velocity of 900 k m h - 1 loops a vertical circular loop. If the maximum force pressing the pilot against the seat is five times his weight, what would be the diameter (in m ) of the loop? [ g = 10 m s - 2 ]

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