NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
A particle is suspended by a light vertical inelastic string of length l from a fixed support. At its equilibrium position, it is projected horizontally with a speed 6 g l . What is the ratio of the tension in the string in its horizontal position to when the particle is vertically above the point of support?
Correct answer
4
Step-by-step solution
For a given u = 6 g l At the horizontal position, T 1 = m v 1 2 l = 4 mg .......... (i) At the highest point T 2 + m g = m v 2 2 l = 2 mgT 2 = mg ......... (ii) From the above equations, we get T 1 T 2 = 4