A 1 kg block B rests as shown on a bracket A of the same mass. Constant forces F 1 = 20 N and F 2 = 8 N start to act at a time t = 0 when the distance of block B from the pulley is 50 cm . Time (in s ) when block B reaches the pulley is t . Find the value of 10 t .

Step-by-step solution

First, find out the acceleration of A so for this ⇒ a = 20 - 2 F 2 = 20 - 2 × 8 a A = 4   m   s - 2 Now use pseudo concept (in which A is the non-inertial frame) ⇒ 8 - 4 = 4   m   s - 2 Now 50 100 = 1 2 × 4 × t 2 t = 1 2 = 0.5   s ⇒   10 t = 5   s