NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
The figure shows the position-time x - t graph of one-dimensional motion of a body of mass 0 . 4 kg . The magnitude of each impulse is
Options
- A0 . 4   N   s
- B0 . 8   N   s
- C1 . 6   N   s
- D0 . 2   N   s
Correct answer
B. 0 . 8   N   s
Step-by-step solution
From the graph, it is a straight line so, uniform motion. Because of impulse direction of velocity changes as can be seen from the slope of the graph. I n i t i a l   v e l o c i t y   v 1 = 2 2 = 1   m  s - 1 F i n a l   v e l o c i t y   v 2 = - 2 2 = - 1   m  s - 1 p i = m v 1 = 0.4   N  s p f = m v 2 = - 0.4   N  s J = p f - p i = - 0.4 - 0.4 = - 0.8   N   s     ( J = i m p u l s e ) ∴     J = 0.8   N  s