Block B starts from rest and accelerates as a B = 12 t m s - 2 . Simultaneously another end of the string is pulled with constant acceleration a 0 . If at t = 3 s , block A comes to rest then the value of a 0 (in m s - 2 ) is equal to

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Correct answer: 18

12 t – 2 a A – a 0 = 0 ⇒ a A = 6 t - a 0 2 ∫ 0 v d v = ∫ 0 t 6 t - a 0 2 d t ⇒ v = 3 t 2 - a 0 2 t ⇒ v = 0, ⇒ 3 t = a 0 2 ⇒ a 0 = 6 t

Block B starts from rest and accelerates as a B = 12 t m s - 2 . Simultaneously another end of the string is pulled with constant acceleration a 0 . If at t = 3 s , block A comes to rest then the value of a 0 (in m s - 2 ) is equal to

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