NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
A wooden wedge of mass M and inclination angle α rests on a smooth floor. A block of mass m is kept on wedge. A force P → is applied on the wedge as shown in figure, such that a block remains stationary with respect to wedge. The magnitude of force P → is
Options
- AM + m g t a n α
- Bg t a n α
- Cm g cos α
- D( M + m ) g cosec α
Correct answer
A. M + m g t a n α
Step-by-step solution
Since, P = ( M + m ) a Now as in free body diagram of block, m a cos α = m g sin α ∴ a = g sin α cos α = g tan α or P = M + m g tan α