A block of mass m is kept on an inclined plane of a lift moving down with an acceleration of 2 m s - 2 . What should be the coefficient of friction for the block to move down with constant velocity relative to lift? The angle of inclination of the wedge is 30 ° . g = 10 m s - 2

Step-by-step solution

g eff = g - 2 = 8  m s - 2 m 8 sin 30 o = μ . m 8 cos 30 o ⇒ μ = tan 30 o ⇒         m g - a sin  θ = μ m g - a cos  θ ⇒         μ = tan  θ = tan  3 0 o = 1 3