A string of length 1 m is fixed at one end with a bob of mass 100 g and the string makes 2 π r e v s - 1 around a vertical axis through a fixed point. The angle of inclination of the string with vertical is

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Correct answer: D. cos - 1 ⁡ 5 / 8

T cos ⁡ θ = m g .....(i) T sin ⁡ θ = m ω 2 r .....(ii) So tan ⁡ θ = ω 2 r g ; ⇒ sin ⁡ θ cos ⁡ θ = ω 2 l sin ⁡ θ g ⇒ cos ⁡ θ = g ω 2 l ⇒ cos ⁡ θ = 10 16 × 1 = 5 8 ⇒ θ = cos - 1 5 8

A string of length 1 m is fixed at one end with a bob of mass 100 g and the string makes 2 π r e v s - 1 around a vertical axis through a fixed point. The angle of inclination of the string with vertical is

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