The pulleys and strings shown in the figure are smooth and of negligible mass. For the system to remain in equilibrium, the angle θ should be

Step-by-step solution

The tension in both the strings will be same. For equilibrium in vertical direction for body B we have 2 m g = 2 T cos θ ∴ 2 m g = 2 ( m g ) cos θ ( ∵ T = m g at equilibrium) ∴ cos θ = 1 2 ⇒ θ = 45 °