A body moves in a circular path of the radius R with deceleration so that at any moment of time its tangential and normal acceleration are equal in magnitude. At the initial moment t = 0 , the velocity of the body is v 0 then the velocity o

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A body moves in a circular path of the radius R with deceleration so that at any moment of time its tangential and normal acceleration are equal in magnitude. At the initial moment t = 0 , the velocity of the body is v 0 then the velocity of the body after it has moved S at any time will be -

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Correct answer: B. v = v 0 e - S R

a T = a N vdv ds = - v 2 R (-ve because it is a retardation) and s is the distance. covered tangentially on circular path on integrating we get ∫ v 0 v dv v = ∫ 0 s - ds R log v v 0 v = 1 R - 1 s log v v 0 = - s R v = v 0 e - s R

A body moves in a circular path of the radius R with deceleration so that at any moment of time its tangential and normal acceleration are equal in magnitude. At the initial moment t = 0 , the velocity of the body is v 0 then the velocity of the body after it has moved S at any time will be -

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