A 2 kg stone tied at the end of a string 1 m long is whirled along a vertical circle at a constant speed of 4 m s - 1 . What will be the tension in the string (in newton) at the bottom-most point?

Step-by-step solution

Here, m = 2   k g ,   r = 1   m ,   v = 4   m   s - 1 Tension at the bottom of the circle, T L = m g + m v 2 r = 2 0 + 2 × 4 2 1 = 52   N