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The velocity and acceleration vectors of a particle undergoing circular motion are v → = 2 i ^ m s - 1 and a → = 2 i ^ + 4 j ^ m s - 2 respectively at an instant of time. What is the radius (in m ) of the circle?

Correct answer

1

Step-by-step solution

It can be observed that the component of acceleration perpendicular to velocity is a = 4   m   s - 2 ∴    Radius = v 2 a c = 2 2 4 = 1   m

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