NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
A 0.5 kg ball moving with a speed of 12 m s - 1 strikes a hard wall at an angle of 30 ° with the wall. It is reflected with the same speed at the same angle. If the ball is in contact with the wall for 0.25 s , the average force acting on the wall is
Options
- A96 N
- B48 N
- C24 N
- D12 N
Correct answer
C. 24 N
Step-by-step solution
Here, F × t = change in momentum = 2 m v sin θ ∴ F = 2 m v sin θ t = 2 × 0.5 × 12 × sin 30 o 0.25 = 48 × 1 2 = 24 N