NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
A monkey of mass 20 kg is holding a vertical rope. The rope will not break when a mass of 25 kg is suspended from it, but will break if the mass exceeds 25 kg. What is the maximum acceleration with which the monkey can climb up along the rope? g = 1 0 m s - 2
Options
- A2 .5   m   ​  s − 2
- B5 m s − 2
- C10 m s − 2
- D25 m s − 2
Correct answer
A. 2 .5   m   ​  s − 2
Step-by-step solution
For monkey, we can write Mg - T = Ma or M(g + a) = T ....(i) for suspended weight, T ≤ mg ....(ii) T ≤ 25 × 10 or 250 N [breaking strength] ∴ Equation (i) becomes 20.(10 + a) ≤ 250 ⇒ a ≤ 50 2 0 or a ≤ 2 . 5 m s - 2 ∴ a max = 2.5 m s -2