NTA Abhyas JEE Main2020PhysicsLaws of MotionPractice
What is the maximum value of the force F (in newton) such that the block shown in the arrangement, does not move?
Correct answer
20
Step-by-step solution
Free body diagram (FBD) of the block (shown by a dot) is shown in figure. For vertical equilibrium of the block, N = m g + F sin 60 ° = 3 g + 3 F 2 … . i For no motion, force of friction f ≥ F cos 60 ° o r ° μ N ≥ F cos 60 ° o r 1 2 3 3 g + 3 F 2 ≥ F 2 o r g ≥ F 2 o r F ≤ 2 g o r 20 N Therefore, maximum value of F is 20 N.