Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET201921 Apr 2019Evening ShiftMathematicsIndefinite IntegrationActual

∫ x 2 2 sin π 4 + x + e x d x =

Options

  1. Ax 2 + 2 x - 2 sin x + - x 2 + 2 x + 2 cos x + x 2 - 2 x + 2 e x + C
  2. B- x 2 + 2 x - 2 sin x + x 2 + 2 x - 2 cos x + x 2 - 2 x + 2 e x + C
  3. Cx 2 + 2 x + 2 sin x + - x 2 - 2 x - 2 cos x + x 2 - 2 x + 2 e x + C
  4. Dx 2 - 2 x - 2 sin x + - x 2 + 2 x - 2 cos x + x 2 - 2 x + 2 e x + C

Correct answer

A. x 2 + 2 x - 2 sin x + - x 2 + 2 x + 2 cos x + x 2 - 2 x + 2 e x + C

Step-by-step solution

The integral expression is given as, I = ∫ x 2 2 sin π 4 + x + e x d x ⇒ I = ∫ x 2 2 sin π 4 cos x + sin x cos π 4 + e x d x ⇒ I = ∫ x 2 2 1 2 cos x + 1 2 sin x + e x d x Further simplifying we get, ⇒ I = ∫ x 2 cos x + sin x + e x d x ⇒ I = ∫ x 2 ( cos x + sin x ) d x + ∫ x 2 e x d x As we know from integration by parts, ∫ u v d x = u ∫ v d x - ∫ d u d x · ∫ v d x d x ⇒ I = x 2 ∫ cos x + sin x d x - &

Practice Indefinite Integration on Quantrex Academy →

More from Indefinite Integration

If 5 x x -2 dx = ax + b | x -2 x |+ c , then a + b = 2025x Cos ⁻¹ ( 1-x^2 1+x^2 ) d x(x>0)= 2025d x (1+ x ) x-x^2 = 2025If x x x+1 ~d x= f (x)+ k , then f ( 4 )= 2025If x^4+1 x^2+1 d x=A x^3+B x^2+C x+D Tan ⁻¹ x+E , then A+B+C+D= 2025If x^2-x+2 x^2+x+2 d x=x- (f(x))+ 2 7 Tan ⁻¹(g(x))+c , then f (-1)+ 7 ~g (-1)= 2025(x- 3 ) (x+ 6 ) d x= 2025If a x+3 x 5 x+2 x d x= 26 29 x- k 29 |5 x+2 x|+c , then |a+k|= 2025 Full Indefinite Integration list All AP EAMCET PYQs