The electric field on two sides of a large charged plate is shown in the diagram. The charge density on the plate in S.I. units is given by ( ε 0 is the permittivity of free space in S.I. units)

Step-by-step solution

From the figure, it is clear that the plate is placed in an external electric field. Let the electric field due to plate be E, and E 0 is the external electric field. ∴ E 0 + E = 1 2 V m - 1 E 0 - E = 8 V m - 1 Solving equations, E = 2 V m -1 and E 0 = 10 V m -1 Now, electric field due to plate = σ 2 ε 0 = 2 ∴ σ = 4 ε 0