Calculate the couple (in μ N m ) acting on a magnet of length 10 cm and pole strength 15 A m , kept in a field of B = 2 × 10 - 5 T at an angle of 30 ° .

Step-by-step solution

C = M B sin ⁡ θ = m × 2 l × 2 × 10 - 5 sin ⁡ 30 ° = 15 × 10 × 10 - 2 × 2 × 10 - 5 × 1 2 = 15 × 10 - 6   N   m