NTA Abhyas JEE Main2020PhysicsMagnetic Properties of MatterPractice
The potential of the electric field produced by point charge at any point ( x , y , z ) is given by V = 3 x 2 + 5 , where x , y are in metres and V is in volts. The intensity of the electric field at ( - 2 m , 1 m , 0 m ) is
Options
- A+ 17 V m - 1
- B- 17 V m - 1
- C+ 12 V m - 1
- D- 12 V m - 1
Correct answer
C. + 12 V m - 1
Step-by-step solution
Potential ( V ) = 3 x 2 + 5 Intensity of the electric field= -d V d x = 6 x ∴ E a t x = - 2 =- 6 ( - 2 ) =+ 12 V m - 1