The fraction of atoms of a radioactive element that decays in& 6...

\dfrac{7}{8}fraction decays in&6days$<br /><br />$\dfrac{1}{8}fraction is active after&6days<br /><br />By using,&N = {N}_{0}\left(\dfrac{1}{2}\right)t / {T}_{1/2}$<br /><br />$N = \dfrac{N0}{2n}$<br /><br />$\dfrac{N0}{8} = \dfrac{N0}{2n}$<br /><br />$n = 3$</p><p>$6days = halflives$<br /><br />$t\dfrac{1}{2} = 2days$<br /><br />$10days = 5{t}_{1/2}$<br /><br />$N = \dfrac{N0}{25} = \dfrac{N0}{32}$<br /><br />Sodecay = {N}_{0} - \dfrac{N0}{32} = \dfrac{31}{32}{N}_{0}$