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If 200 MeV energy is released in the fission of a single nucleus of 92 U 235 . How many fissions must occur per second to produce a power of 1 kW ?

Options

  1. A3.125 × 10 13
  2. B6.250 × 10 13
  3. C1.525 × 10 13
  4. DNone of these

Correct answer

A. 3.125 × 10 13

Step-by-step solution

We know that 1 kW = 1 × 10 3 J s - 1 Also, 1.6 × 10 - 9 J = 1 e V ∴ 200 M e V = 200 × 1.6 × 10 - 19 × 10 6 J Number of fissions = P o w e r E n e r g y r e l e a s e d = 10 3 200 × 1.6 × 10 - 13 = 3.125 × 10 13

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