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NTA Abhyas JEE Main2020PhysicsNuclear PhysicsPractice

A U 238 nucleus originally at rest, decays by emitting an alpha particle having a speed u . Due to this emission, the residual nucleus recoils with a speed n u 234 . What is the value of n ?

Correct answer

4

Step-by-step solution

Apply conservation of linear momentum 4 u ⁡ - 2 3 4 v ⁡ = 0 ⇒ v ⁡ = 4 u ⁡ 2 3 4 n = 4

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