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NTA Abhyas JEE Main2020PhysicsNuclear PhysicsPractice

M p denotes the mass of a proton and M n that of a neutron. A given nucleus, of binding energy B , contains Z protons and N neutrons. The mass M ( N , Z ) of the nucleus is given by ( c is the velocity of light)

Options

  1. AM ( N , Z ) = N M n + Z M p - B c 2
  2. BM N , Z = N M n + Z M p + B c 2
  3. CM ( N ,   Z ) = N M n + Z M p - B / c 2
  4. DM N , Z = N M n + Z M p + B / c 2

Correct answer

C. M ( N ,   Z ) = N M n + Z M p - B / c 2

Step-by-step solution

Mass defect = mass of nucleon - mass of nucleus B = Z M p + N M n - M N , Z c 2 ⇒ M ( M , Z ) = Z M p + N M n - B / c 2

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