NTA Abhyas JEE Main2020PhysicsNuclear PhysicsPractice
When a proton, anti-proton annihilate, the energy released is
Options
- A3.0 × 10 - 10 J
- B28.8 × 10 - 10 J
- C6 × 10 - 10 J
- D9 × 1 0 - 1 0 J
Correct answer
A. 3.0 × 10 - 10 J
Step-by-step solution
Assuming proton and antiproton are at rest and let them mutually annihilate. Then the energy per photon: Einstein's mass energy relation , the energy released is Δ E = Δ m c 2 Where, c is the speed of light and   Δ m is mass. Given, Δ m = 1.67   ×   10 - 27   k g   ,   c   =   3   ×   10 8   m  s - 1 ∴       Δ E = 1.67   ×   10 - 27   ×   3   ×   10 8 2