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Using the following data Mass of hydrogen atom = 1 . 00783 u Mass of neutron = 1 . 00867 u Mass of nitrogen atom ( 7 N 14 )= 14 . 00307 u The calculated value of the binding energy of the nucleus of the nitrogen atom ( 7 N 14 ) is close to

Options

  1. A56     MeV
  2. B98     MeV
  3. C104 MeV
  4. D112     MeV

Correct answer

C. 104 MeV

Step-by-step solution

The binding energy of nucleus may be defined as the energy equivalent to the mass defect of the nucleus. If ∆ m is mass defect than according to Einstein's mass energy relation. Binding Energy = ∆ m c 2 = Z m p + A - Z m n - M c 2 = 7 × 1.00783 + 7 × 1.00867 - 14.00307 c 2 o r B E = 0.1124 × 931.5 MeV or BE = 104.6   MeV

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