NTA Abhyas JEE Main2020PhysicsNuclear PhysicsPractice
The half-life of a radioactive nuclide is 20 h . It is found that the fraction ( 1 x ) of original activity remains after 40 hours ? What is the value of x ?
Correct answer
4
Step-by-step solution
We have t t 1 / 2 = 4 0 hours 20 hours = 2 Thus, A = A 0 2 t / t 1 / 2 = A 0 2 2 = A 0 4 So, one fourth of the original activity will remain after 40 hours.