Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET201725 Apr 2017Evening ShiftMathematicsIndefinite IntegrationActual

If 0 < a < 1 , then d x 1-2 a x+a^2 =

Options

  1. A1 1-a^2 Tan ⁻¹ [ 1+a 1-a x 2 ]+c
  2. B2 1+a^2 Tan ⁻¹ [ 1-a 1+a x 2 ]+c
  3. C2 1-a^2 Tan ⁻¹ [ 1+a 1-a x 2 ]+c
  4. D2 1+a Tan ⁻¹ [ 1-a^2 1+a^2 x 2 ]+c

Correct answer

C. 2 1-a^2 Tan ⁻¹ [ 1+a 1-a x 2 ]+c

Step-by-step solution

No solution. Refer to answer key.

Practice Indefinite Integration on Quantrex Academy →

More from Indefinite Integration

If 5 x x -2 dx = ax + b | x -2 x |+ c , then a + b = 2025x Cos ⁻¹ ( 1-x^2 1+x^2 ) d x(x>0)= 2025d x (1+ x ) x-x^2 = 2025If x x x+1 ~d x= f (x)+ k , then f ( 4 )= 2025If x^4+1 x^2+1 d x=A x^3+B x^2+C x+D Tan ⁻¹ x+E , then A+B+C+D= 2025If x^2-x+2 x^2+x+2 d x=x- (f(x))+ 2 7 Tan ⁻¹(g(x))+c , then f (-1)+ 7 ~g (-1)= 2025(x- 3 ) (x+ 6 ) d x= 2025If a x+3 x 5 x+2 x d x= 26 29 x- k 29 |5 x+2 x|+c , then |a+k|= 2025 Full Indefinite Integration list All AP EAMCET PYQs