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In the figure, the reverse breakdown voltage of a Zener diode is 5. 6   V , then the current I z through the diode is

Options

  1. A17   mA
  2. B15   mA
  3. C10   mA
  4. D7   mA

Correct answer

C. 10   mA

Step-by-step solution

For zener break down potential difference across 800 Ω resistor will be 5 . 6 V V z = 5 . 6 V i 2 = V 2 800 = 5 . 6 800 = 7 mA ΔV across 200 Ω = 9 - 5 . 6 = 3 . 4 V i 1 = 3 . 4 200 = 17 mA i 1 = i 2 + i z i z = 17 mA - 7 mA = 10 mA

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