NTA Abhyas JEE Main2020PhysicsSemiconductorsPractice
In the following common emitter configuration a N P N transistor with current gain β = 100 is used. The output voltage of the amplifier will be
Options
- A10 m V
- B0.1 V
- C1.0 V
- D10 V
Correct answer
C. 1.0 V
Step-by-step solution
V o l t a g e   g a i n   = O u t p u t   v o l t a g e I n p u t   v o l t a g e   V o u t   =   V i n  ×   V o l t a g e   g a i n   V o u t   =   V i n    ×  C u r r e n t   g a i n  ×   R e s i s t a n c e   g a i n =   V i n × β × R o R i = 1 0 - 3 × 100 × 10 1 = 1 V