NTA Abhyas JEE Main2020PhysicsSemiconductorsPractice
The output Y of the combination of logic gates shown is equal to
Options
- AA
- BA ¯
- CA + B
- DAB
Correct answer
A. A
Step-by-step solution
From boolen algebra we have A . (A + B) = A
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A. A
From boolen algebra we have A . (A + B) = A