NTA Abhyas JEE Main2020PhysicsSemiconductorsPractice
In the circuit shown in figure, the base current I B is 10   μA and the collector current is 5 . 2   mA . The voltage ( V BE ) across the base and emitter is
Options
- A0 . 1   V
- B0 . 5 V
- C0 . 25   V
- D0 . 7   V
Correct answer
B. 0 . 5 V
Step-by-step solution
V B E = V C C - I B R B V B E = 5 . 5 - 10 × 10 - 6 × 5 × 10 5 = 0 . 5 V