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In the figure shown, R B = 500 kΩ , R C = 8 kΩ , V BB = 10 .6 V and V CC = 20 V . The current amplification factor β = 100 and V BE = 0 .6 V . Mark the incorrect statement.

Options

  1. AI B = 20 μA
  2. BV CB = 3 .4   V
  3. CV CE = 2 .8 V
  4. Dthe transistor is in active region

Correct answer

C. V CE = 2 .8 V

Step-by-step solution

V BB   –   I B R B =   V BE 10 . 6 - 5 × 10 5 × I B = 0 . 6 ⇒ I B = 20   μA I C = 100   I B = 2000   μA V CE =   V CC   – I C R C = 20 - 0 . 002 × 8000 = 4   V V CB = 20 - 0 . 002 × 8000 - 0 . 6 = 3 . 4   V

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