NTA Abhyas JEE Main2020PhysicsSemiconductorsPractice
In the figure shown, R B = 500 kΩ , R C = 8 kΩ , V BB = 10 .6 V and V CC = 20 V . The current amplification factor β = 100 and V BE = 0 .6 V . Mark the incorrect statement.
Options
- AI B = 20 μA
- BV CB = 3 .4   V
- CV CE = 2 .8 V
- Dthe transistor is in active region
Correct answer
C. V CE = 2 .8 V
Step-by-step solution
V BB   –   I B R B =   V BE 10 . 6 - 5 × 10 5 × I B = 0 . 6 ⇒ I B = 20   μA I C = 100   I B = 2000   μA V CE =   V CC   – I C R C = 20 - 0 . 002 × 8000 = 4   V V CB = 20 - 0 . 002 × 8000 - 0 . 6 = 3 . 4   V