Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020PhysicsSemiconductorsPractice

A transistor, connected in common emitter configuration, has input resistance R in = 2 k Ω and load resistance of 5 k Ω . If β = 6 0 and an input signal 12 mV is applied, find the power gain.

Options

  1. A9000
  2. B4000
  3. C6000
  4. D8000

Correct answer

A. 9000

Step-by-step solution

Power gain = β 2 R L R BE = 6 0 2 5 2 = 1 8 0 0 0 2 = 9 0 0 0

Practice Semiconductors on Quantrex Academy →

More from Semiconductors

The output Y for the given inputs A and B to the circuit is: 2026Refer to the logic circuit given below. For two inputs (A=1, B=1) and (A=0, B=1) , output (Y) will be __________. 2026The maximum rated power of the LED is 2 mW and it is used in the circuit with input voltage of 5 V as shown in the figure below. The current through resistance R_S is 0.5 mA. The m 2026In a semiconductor p-n diode, the doping concentrations on p-side and n-side are 10¹⁵ atoms/cm ^3 and 10¹⁸ atoms/cm ^3 , respectively. Which one of the following statements is true 2026For the given logic circuit, which of the following inputs combination will make both LED -1 and LED -2 to glow? 2026Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A: A diode under reverse-biased condition provides very small current 2026A diode has Zener voltage of 10 V and maximum power dissipation of 0.5 W, then the minimum resistance to be used in series with this diode for safety when it is connected to a 25 V 2026Two 4 bits binary numbers, A = 1101 and B = 1010 are given in the inputs of a logic circuit shown in figure below. The output (Y) will be: 2026 Full Semiconductors list All NTA Abhyas JEE Main PYQs