NTA Abhyas JEE Main2020PhysicsSemiconductorsPractice
The transfer characteristic curve of a transistor, having input and output resistance 100 Ω and 100 k Ω respectively, is shown in the figure. The voltage and power gain, are respectively:
Options
- A5 × 10 4 , 2.5 × 10 6
- B2.5 × 10 4 , 2.5 × 10 6
- C5 × 10 4 , 5 × 10 6
- D5 × 10 4 , 5 × 10 5
Correct answer
A. 5 × 10 4 , 2.5 × 10 6
Step-by-step solution
Current gain β = Δ I C Δ I B = 5 × 10 - 3 100 × 10 - 6 = 50 Voltage gain ( A V ) = β R o u t R i n = 50 × 100 × 10 3 100 = 5 × 10 4 Power gain = A V × β = 50 × 5 × 10 4 = 2.5 × 10 6