NTA Abhyas JEE Main2020PhysicsSemiconductorsPractice
In the following common emitter configuration, an NPN transistor with current gain β = 100 is used. The output voltage of the amplifier will be
Options
- A10   mV
- B0 . 1   V
- C1 . 0   V
- D10   V
Correct answer
C. 1 . 0   V
Step-by-step solution
V o l t a g e   g a i n   = O u t p u t   v o l t a g e I n p u t   v o l t a g e   V o u t   =   V i n  ×   V o l t a g e   g a i n   V out   =   V in   ×  Current   gain  ×  Resistance   =   V i n × β × R o R i = 10 - 3 × 100 × 10 1 = 1   V