NTA Abhyas JEE Main2020PhysicsSemiconductorsPractice
In a common-emitter configuration of a transistor, the base current I E = 2 μ A , α = 0.9 then the value of I C is
Options
- A3 . 0   μ A
- B2 . 25   μ A
- C4 . 9   μ A
- D1 . 8 μ A
Correct answer
D. 1 . 8 μ A
Step-by-step solution
We know that current gain is given by, α = I c I b ∴ I c = α × I b = 0.9 × 2 = 1.8   μ A