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In a common emitter NPN transistor, 10 10 electrons enter the emitter in 10 - 6 s when it is connected to the battery. About 5 % of electrons recombine with holes in the base. The current gain of the transistor is e = 1.6 × 10 - 19 C

Options

  1. A0 . 98
  2. B19
  3. C49
  4. D0 . 95

Correct answer

B. 19

Step-by-step solution

Current gain of common emitter β = i C i B β = 95 % o f i E 5 % o f i E β = 95 5 = 19

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