NTA Abhyas JEE Main2020PhysicsSemiconductorsPractice
A change of 8 . 0   mA in the emitter current brings a change of 7 . 9   mA in the collector current. The values of α and β are
Options
- A0.99 ,   90
- B0.96 ,   79
- C0.97 ,   99
- D0.99 ,   79
Correct answer
D. 0.99 ,   79
Step-by-step solution
Given that, change in emitter current, ∆ I E = 8   mA and change in collector current, ∆ I C = 7.9   mA . We know that, α = ∆ I C ∆ I E ⇒ α= 7.9 8 ⇒ α ≈ 0 . 99 Also, we know that β = α 1 - α ⇒β = 7.9 8 1 - 7.9 8 = 7.9 8 - 7.9 ⇒ β = 7.9 0.1 = 79 Hence, the required answer is α = 0 . 99 and β = 79 .