In a common-emitter transistor amplifier, the output resistance is 500 kΩ and the current gain β = 49 . If the power gain of the amplifier is 5 × 10 6 , the input resistance is

Step-by-step solution

Given, R o =   500   kΩ , β   = 49   and P = 5 × 10 6 We have               P = β   2   R o R i 5 × 10 6 = 49 2 × 500 × 10 3 R i R i = 49 × 49 × 500 × 10 3 5 × 10 6 = 240   Ω